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	<title>Converse of intermediate value theorem - Revision history</title>
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		<title>Vipul: Created page with &#039;==Statement==  Suppose &lt;math&gt;X&lt;/math&gt; is a topological space that satisfies the conclusion of the intermediate value theorem: For any continuous function &lt;math&gt;f:X \to \R…&#039;</title>
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		<updated>2009-12-24T01:04:05Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;#039;==Statement==  Suppose &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; is a &lt;a href=&quot;/wiki/Topological_space&quot; title=&quot;Topological space&quot;&gt;topological space&lt;/a&gt; that satisfies the conclusion of the &lt;a href=&quot;/wiki/Intermediate_value_theorem&quot; title=&quot;Intermediate value theorem&quot;&gt;intermediate value theorem&lt;/a&gt;: For any continuous function &amp;lt;math&amp;gt;f:X \to \R…&amp;#039;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;==Statement==&lt;br /&gt;
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Suppose &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; is a [[topological space]] that satisfies the conclusion of the [[intermediate value theorem]]: For any continuous function &amp;lt;math&amp;gt;f:X \to \R&amp;lt;/math&amp;gt;, and two elements &amp;lt;math&amp;gt;x_1,x_2 \in X&amp;lt;/math&amp;gt; such that &amp;lt;math&amp;gt;f(x_1) &amp;lt; f(x_2)&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;f(X)&amp;lt;/math&amp;gt; must contain &amp;lt;math&amp;gt;[f(x_1),f(x_2)]&amp;lt;/math&amp;gt;.&lt;br /&gt;
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Then, &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; is a [[connected space]].&lt;br /&gt;
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==Related facts==&lt;br /&gt;
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===Converse===&lt;br /&gt;
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* [[Intermediate value theorem]]&lt;br /&gt;
==Proof==&lt;br /&gt;
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&amp;#039;&amp;#039;&amp;#039;Given&amp;#039;&amp;#039;&amp;#039;: A topological space &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; such that for any continuous function &amp;lt;math&amp;gt;f:X \to \R&amp;lt;/math&amp;gt;, and two elements &amp;lt;math&amp;gt;x_1,x_2 \in X&amp;lt;/math&amp;gt; such that &amp;lt;math&amp;gt;f(x_1) &amp;lt; f(x_2)&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;f(X)&amp;lt;/math&amp;gt; must contain &amp;lt;math&amp;gt;[f(x_1),f(x_2)]&amp;lt;/math&amp;gt;.&lt;br /&gt;
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&amp;#039;&amp;#039;&amp;#039;To prove&amp;#039;&amp;#039;&amp;#039;: &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; is connected.&lt;br /&gt;
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&amp;#039;&amp;#039;&amp;#039;Proof&amp;#039;&amp;#039;&amp;#039;: Suppose not, i.e., suppose &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; is not connected. Then, &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; is a union of two nonempty disjoint open subsets &amp;lt;math&amp;gt;U&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;V&amp;lt;/math&amp;gt;. Consider the function &amp;lt;math&amp;gt;f:X \to \R&amp;lt;/math&amp;gt; defined by &amp;lt;math&amp;gt;f(x) = 0 \ \forall \ x \in U&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;f(x) = 1 \ \forall \ x \in V&amp;lt;/math&amp;gt;. This is a continuous function (in fact, all its fibers are open).&lt;br /&gt;
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Pick &amp;lt;math&amp;gt;x_1 \in U&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;x_2 \in V&amp;lt;/math&amp;gt;. By our construction, &amp;lt;math&amp;gt;f(x_1) &amp;lt; f(x_2)&amp;lt;/math&amp;gt;, so by the given data, &amp;lt;math&amp;gt;f(X)&amp;lt;/math&amp;gt; should contain the interval &amp;lt;math&amp;gt;[f(x_1),f(x_2)] = [0,1]&amp;lt;/math&amp;gt;. But this contradicts the fact that the image of &amp;lt;math&amp;gt;f&amp;lt;/math&amp;gt; is the two-element set &amp;lt;math&amp;gt;\{ 0, 1 \}&amp;lt;/math&amp;gt;.&lt;br /&gt;
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Thus, our original assumption that &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; is not connected cannot hold. Hence, &amp;lt;math&amp;gt;X&amp;lt;/math&amp;gt; must be connected.&lt;/div&gt;</summary>
		<author><name>Vipul</name></author>
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