Homotopy of maps induces chain homotopy: Difference between revisions
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==Construction== | ==Construction== | ||
To construct a chain homotopy, we | To construct a chain homotopy, we first define a certain <math>(q+1)</math>-singular chain in <math>\Delta^q \times I</math>. Let <math>e_i</math> be the vertex of the <math>q</math>-simplex with only the <math>i^{th}</math> coordinate nonzero. Let <math>e_i^0 = (e_i,0) \in \Delta^q \times I</math> and <math>e_i^1 = (e_1,1) \in \Delta^q \times I</math>.This is defined as: | ||
<math>D = \sum_{i=0}^q (-1)^i S(e_0^0, \ldots, e_i^0, e_i^1, \ldots, e_q^1)</math> | |||
where <math>S</math> of a tuple is the simplex with those as vertices. This clearly gives a singular chain in <math>\Delta^q \times I</math>. | |||
For a given homotopy <math>F: X \times I \to Y</math> the map <math>D_F</math> is defined as: | |||
<math>\sigma \mapsto (\sigma \times id) \circ D</math> | |||
==Proof== | |||
Latest revision as of 19:47, 11 May 2008
Statement
Let be a homotopy between . In other words and for all . Then, there is a chain homotopy from the singular complex of to the singular complex of such that . In fact, the map sending to is a homomorphism in the sense that if is the composite of and , .
Construction
To construct a chain homotopy, we first define a certain -singular chain in . Let be the vertex of the -simplex with only the coordinate nonzero. Let and .This is defined as:
where of a tuple is the simplex with those as vertices. This clearly gives a singular chain in .
For a given homotopy the map is defined as: