Homotopy of real projective space: Difference between revisions

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===The case <math>n = 1</math>===
===The case <math>n = 1</math>===


In the case <math>n = 1</math> we get <math>\mathbb{P}^1(\R)</math> is homeomorphic to the [[circle]] <math>S^1</math>. We have <math>\pi_0(S^1)</math> is the one-point space (the trivial group), <math>\pi_1(S^1) \cong \mathbb{Z}</math> is the group of integers, and <math>\pi_k(S^1)</math> is the trivial group.
In the case <math>n = 1</math> we get <math>\mathbb{P}^1(\R)</math> is homeomorphic to the [[circle]] <math>S^1</math>. We have <math>\pi_0(S^1)</math> is the one-point space (the trivial group), <math>\pi_1(S^1) \cong \mathbb{Z}</math> is the group of integers, and <math>\pi_k(S^1)</math> is the trivial group for <math>k > 1</math>.


===The case of higher <math>n</math>===
===The case of higher <math>n</math>===


For <math>n > 1</math>,  <math>\mathbb{P}^n(\R)</math> has the <math>n</math>-[[sphere]] <math>S^n</math> as its double cover and universal cover. In particular, <math>\pi_k(\mathbb{P}^n(\R)) \cong \pi_k(S^n)</math> for <math>k > 1</math> and <math>\pi_1(\mathbb{P}^n(\R) \cong \mathbb{Z}/2\mathbb{Z})</math>. Hence:
For <math>n > 1</math>,  <math>\mathbb{P}^n(\R)</math> has the <math>n</math>-[[sphere]] <math>S^n</math> as its double cover and universal cover. Thus, <math>\pi_k(\mathbb{P}^n(\R)) \cong \pi_k(S^n)</math> for <math>k > 1</math> and <math>\pi_1(\mathbb{P}^n(\R))\cong \mathbb{Z}/2\mathbb{Z}</math>. The problem of computing the homotopy of real projective space therefore reduces to the problem of computing the [[homotopy of spheres]].
 
Hence:


* <math>\pi_0(\mathbb{P}^n(\R))</math> is the one-point space.
* <math>\pi_0(\mathbb{P}^n(\R))</math> is the one-point space.
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* <math>\pi_k(\mathbb{P}^n(\R))</math> is the trivial group for <math>1 < k < n</math>.
* <math>\pi_k(\mathbb{P}^n(\R))</math> is the trivial group for <math>1 < k < n</math>.
* <math>\pi_n(\mathbb{P}^n(\R))</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_n(\mathbb{P}^n(\R))</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_{2n - 1}(\mathbb{P}^n(\R))</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_3(\mathbb{P}^2(\R))</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_k(\mathbb{P}^n(\R)) \cong \pi_k(S^n)</math> is a finite group for <math>k > n, k \ne 2n - 1</math>.
* <math>\pi_k(\mathbb{P}^n(\R)) \cong \pi_k(S^n)</math> is a finite group for <math>k > n, k \ne 2n - 1</math>.

Latest revision as of 19:50, 15 April 2016

This article describes the value (and the process used to compute it) of some homotopy invariant(s) for a topological space or family of topological spaces. The invariant is homotopy group and the topological space/family is real projective space
Get more specific information about real projective space | Get more computations of homotopy group

Statement

This article describes the homotopy groups of the real projective space. This includes the set of path components , the fundamental group , and all the higher homotopy groups.

The case

The space is a one-point space and all its homotopy groups are trivial groups, and the set of path components is a one-point space.

The case

In the case we get is homeomorphic to the circle . We have is the one-point space (the trivial group), is the group of integers, and is the trivial group for .

The case of higher

For , has the -sphere as its double cover and universal cover. Thus, for and . The problem of computing the homotopy of real projective space therefore reduces to the problem of computing the homotopy of spheres.

Hence:

  • is the one-point space.
  • is the cyclic group:Z2, i.e., .
  • is the trivial group for .
  • is isomorphic to , the group of integers.
  • is isomorphic to , the group of integers.
  • is a finite group for .