Homotopy of real projective space: Difference between revisions

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===The case <math>n = 0</math>===
===The case <math>n = 0</math>===


The space <math>\R\mathbb{P}^0</math> is a one-point space and all its [[homotopy group]]s are trivial groups, and the set of path components is a one-point space.
The space <math>\mathbb{P}^0(\R)</math> is a one-point space and all its [[homotopy group]]s are trivial groups, and the set of path components is a one-point space.


===The case <math>n = 1</math>===
===The case <math>n = 1</math>===


In the case <math>n = 1</math> we get <math>\R\mathbb{P}^1</math> is homeomorphic to the [[circle]] <math>S^1</math>. We have <math>\pi_0(S^1)</math> is the one-point space (the trivial group), <math>\pi_1(S^1) \cong \mathbb{Z}</math> is the group of integers, and <math>\pi_k(S^1)</math> is the trivial group for <math>k > 1</math>.
In the case <math>n = 1</math> we get <math>\mathbb{P}^1(\R)</math> is homeomorphic to the [[circle]] <math>S^1</math>. We have <math>\pi_0(S^1)</math> is the one-point space (the trivial group), <math>\pi_1(S^1) \cong \mathbb{Z}</math> is the group of integers, and <math>\pi_k(S^1)</math> is the trivial group for <math>k > 1</math>.


===The case of higher <math>n</math>===
===The case of higher <math>n</math>===


For <math>n > 1</math>,  <math>\mathbb{P}^n(\R)</math> has the <math>n</math>-[[sphere]] <math>S^n</math> as its double cover and universal cover. In particular, <math>\pi_k(\mathbb{P}^n(\R)) \cong \pi_k(S^n)</math> for <math>k > 1</math> and <math>\pi_1(\mathbb{P}^n(\R) \cong \mathbb{Z}/2\mathbb{Z})</math>. Hence:
For <math>n > 1</math>,  <math>\mathbb{P}^n(\R)</math> has the <math>n</math>-[[sphere]] <math>S^n</math> as its double cover and universal cover. Thus, <math>\pi_k(\mathbb{P}^n(\R)) \cong \pi_k(S^n)</math> for <math>k > 1</math> and <math>\pi_1(\mathbb{P}^n(\R))\cong \mathbb{Z}/2\mathbb{Z}</math>. The problem of computing the homotopy of real projective space therefore reduces to the problem of computing the [[homotopy of spheres]].


* <math>\pi_0(\R\mathbb{P}^n)</math> is the one-point space.
Hence:
* <math>\pi_1(\R\mathbb{P}^n)</math> is the [[cyclic group:Z2]], i.e., <math>\mathbb{Z}/2\mathbb{Z}</math>.
 
* <math>\pi_k(\R\mathbb{P}^n)</math> is the trivial group for <math>1 < k < n</math>.
* <math>\pi_0(\mathbb{P}^n(\R))</math> is the one-point space.
* <math>\pi_n(\R\mathbb{P}^n)</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_1(\mathbb{P}^n(\R))</math> is the [[cyclic group:Z2]], i.e., <math>\mathbb{Z}/2\mathbb{Z}</math>.
* <math>\pi_{2n - 1}(\R\mathbb{P}^n)</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_k(\mathbb{P}^n(\R))</math> is the trivial group for <math>1 < k < n</math>.
* <math>\pi_k(\R\mathbb{P}^n) \cong \pi_k(S^n)</math> is a finite group for <math>k > n, k \ne 2n - 1</math>.
* <math>\pi_n(\mathbb{P}^n(\R))</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_3(\mathbb{P}^2(\R))</math> is isomorphic to <math>\mathbb{Z}</math>, the group of integers.
* <math>\pi_k(\mathbb{P}^n(\R)) \cong \pi_k(S^n)</math> is a finite group for <math>k > n, k \ne 2n - 1</math>.

Latest revision as of 19:50, 15 April 2016

This article describes the value (and the process used to compute it) of some homotopy invariant(s) for a topological space or family of topological spaces. The invariant is homotopy group and the topological space/family is real projective space
Get more specific information about real projective space | Get more computations of homotopy group

Statement

This article describes the homotopy groups of the real projective space. This includes the set of path components π0, the fundamental group π1, and all the higher homotopy groups.

The case n=0

The space P0(R) is a one-point space and all its homotopy groups are trivial groups, and the set of path components is a one-point space.

The case n=1

In the case n=1 we get P1(R) is homeomorphic to the circle S1. We have π0(S1) is the one-point space (the trivial group), π1(S1)Z is the group of integers, and πk(S1) is the trivial group for k>1.

The case of higher n

For n>1, Pn(R) has the n-sphere Sn as its double cover and universal cover. Thus, πk(Pn(R))πk(Sn) for k>1 and π1(Pn(R))Z/2Z. The problem of computing the homotopy of real projective space therefore reduces to the problem of computing the homotopy of spheres.

Hence:

  • π0(Pn(R)) is the one-point space.
  • π1(Pn(R)) is the cyclic group:Z2, i.e., Z/2Z.
  • πk(Pn(R)) is the trivial group for 1<k<n.
  • πn(Pn(R)) is isomorphic to Z, the group of integers.
  • π3(P2(R)) is isomorphic to Z, the group of integers.
  • πk(Pn(R))πk(Sn) is a finite group for k>n,k2n1.