Mapping cylinder: Difference between revisions

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Further, the inclusion of <math>X</math> in the mapping cylinder is a [[cofibration]], which makes it even nicer.
Further, the inclusion of <math>X</math> in the mapping cylinder is a [[cofibration]], which makes it even nicer.
==Relation with other constructions==
===More general constructions===
{| class="sortable" border="1"
! Name of construction !! Description of construction !! How the mapping cylinder is a special case
|-
| [[specialization of::double mapping cylinder]] || spaces <math>X,Y,Z</math>, with continuous maps from <math>X</math> to <math>Y</math> and <math>X</math> to <math>Z</math>, we take <math>(X \times I) \sqcup Y \sqcup Z</math> and collapse <math>X \times \{ 0 \}</math> and <math>X \times \{ 1 \}</math> onto <math>Z</math> and <math>Y</matH> via the continuous maps || Case where <math>X = Z</math> and the map <math>X \to Z</math> is the identity map.
|}
===More specific constructions===
{| class="sortable" border="1"
! Name of construction !! How it arises as a special case
|-
| [[generalization of::cone space]] || Set <math>Y</math> as a one-point space and <math>f:X \to Y</math> as the map sending everything to one point.
|}

Revision as of 23:09, 9 October 2010

Definition

Let f:XY be a function. Then the mapping cylinder of f is defined as the quotient of the disjoint union of X×I with Y, modulo the equivalence relation:

(x,1)f(x)

Facts

The significance of the mapping cylinder is that it is homotopy-equivalent to Y, and moreover the inclusion of X (say via x(x,0)) in the mapping cylinder is equivalent to the map f.

Thus, starting from an arbitrary continuous map, we have got a homotopy-equivalent map which is an inclusion.

Further, the inclusion of X in the mapping cylinder is a cofibration, which makes it even nicer.

Relation with other constructions

More general constructions

Name of construction Description of construction How the mapping cylinder is a special case
double mapping cylinder spaces X,Y,Z, with continuous maps from X to Y and X to Z, we take (X×I)YZ and collapse X×{0} and X×{1} onto Z and Y via the continuous maps Case where X=Z and the map XZ is the identity map.

More specific constructions

Name of construction How it arises as a special case
cone space Set Y as a one-point space and f:XY as the map sending everything to one point.