Brouwer fixed-point theorem: Difference between revisions

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Any continuous map from the standard <math>n</math>-simplex, to itself, has a fixed point.
Any continuous map from the standard <math>n</math>-simplex, to itself, has a fixed point.
==Relation with other results==
===Results used in proving this===
* [[No-retraction theorem]]
==Proof==
The Brouwer fixed-point theorem follows easily from the [[no-retraction theorem]]. Suppose <math>f:D^n \to D^n</math> is a continuous map with no fixed points. Define a map <math>g:D^n \to S^{n-1}</math>, that sends <math>x \in D^n</math> to the unique point on <math>S^{n-1}</math> that is colllinear with <math>x</math> and <math>f(x)</math> in such a way that <math>x</math> lies between that point and <math>f(x)</math>. We can see that:
* Since <math>f(x)</math> is never equal to <math>x</math>, and <math>x</math> is inside the unit disc, <math>g</math> is well-defined throughout <math>D^n</math>
* <math>g</math> is continuous
* <math>g</math> is a retraction because it fixes every point on <math>S^{n-1}</math>

Revision as of 04:23, 23 May 2007

This article describes a theorem about spheres

Statement

In the language of spheres

Any continuous map from a disc to itself must have a fixed point. In other words, if denotes the spherical disc in , any continuous map must have a point such that .

In the language of simplices

Any continuous map from the standard -simplex, to itself, has a fixed point.

Relation with other results

Results used in proving this

Proof

The Brouwer fixed-point theorem follows easily from the no-retraction theorem. Suppose is a continuous map with no fixed points. Define a map , that sends to the unique point on that is colllinear with and in such a way that lies between that point and . We can see that:

  • Since is never equal to , and is inside the unit disc, is well-defined throughout
  • is continuous
  • is a retraction because it fixes every point on