Brouwer fixed-point theorem: Difference between revisions
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Any continuous map from the standard <math>n</math>-simplex, to itself, has a fixed point. | Any continuous map from the standard <math>n</math>-simplex, to itself, has a fixed point. | ||
==Relation with other results== | |||
===Results used in proving this=== | |||
* [[No-retraction theorem]] | |||
==Proof== | |||
The Brouwer fixed-point theorem follows easily from the [[no-retraction theorem]]. Suppose <math>f:D^n \to D^n</math> is a continuous map with no fixed points. Define a map <math>g:D^n \to S^{n-1}</math>, that sends <math>x \in D^n</math> to the unique point on <math>S^{n-1}</math> that is colllinear with <math>x</math> and <math>f(x)</math> in such a way that <math>x</math> lies between that point and <math>f(x)</math>. We can see that: | |||
* Since <math>f(x)</math> is never equal to <math>x</math>, and <math>x</math> is inside the unit disc, <math>g</math> is well-defined throughout <math>D^n</math> | |||
* <math>g</math> is continuous | |||
* <math>g</math> is a retraction because it fixes every point on <math>S^{n-1}</math> |
Revision as of 04:23, 23 May 2007
This article describes a theorem about spheres
Statement
In the language of spheres
Any continuous map from a disc to itself must have a fixed point. In other words, if denotes the spherical disc in , any continuous map must have a point such that .
In the language of simplices
Any continuous map from the standard -simplex, to itself, has a fixed point.
Relation with other results
Results used in proving this
Proof
The Brouwer fixed-point theorem follows easily from the no-retraction theorem. Suppose is a continuous map with no fixed points. Define a map , that sends to the unique point on that is colllinear with and in such a way that lies between that point and . We can see that:
- Since is never equal to , and is inside the unit disc, is well-defined throughout
- is continuous
- is a retraction because it fixes every point on