Tube lemma: Difference between revisions
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In other words, any open subset containing a slice, contains an [[open cylinder]] that contains the slice. | In other words, any open subset containing a slice, contains an [[open cylinder]] that contains the slice. | ||
==References== | |||
===Textbook references=== | |||
* {{booklink-proved|Munkres}}, Page 168, Lemma 26.8, Chapter 3, Section 26 (the proof is given before the theorem, as Step 1 of the proof of Theorem 26.7 on page 167) | |||
Revision as of 21:50, 20 July 2008
This fact is related to: compactness
This article is about the statement of a simple but indispensable lemma in topology
Statement
Let be a compact space and any topological space. Consider endowed with the product topology. Suppose and is an open subset of containing the entire slice . Then, we can find an open subset of such that:
, and
In other words, any open subset containing a slice, contains an open cylinder that contains the slice.
References
Textbook references
- Topology (2nd edition) by James R. Munkres, More info, Page 168, Lemma 26.8, Chapter 3, Section 26 (the proof is given before the theorem, as Step 1 of the proof of Theorem 26.7 on page 167)