Hausdorffness is refining-preserved: Difference between revisions

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{{topospace metaproperty satisfaction}}
{{topospace metaproperty satisfaction|property = Hausdorff space|metaproperty = refining-preserved property of topological spaces}}
 
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==Statement==
==Statement==



Latest revision as of 04:37, 30 January 2014

This article gives the statement, and possibly proof, of a topological space property (i.e., Hausdorff space) satisfying a topological space metaproperty (i.e., refining-preserved property of topological spaces)
View all topological space metaproperty satisfactions | View all topological space metaproperty dissatisfactions
Get more facts about Hausdorff space |Get facts that use property satisfaction of Hausdorff space | Get facts that use property satisfaction of Hausdorff space|Get more facts about refining-preserved property of topological spaces

Statement

Property-theoretic statement

The property of topological spaces of being a Hausdorff space

Statement with symbols

Suppose (X,τ) is a topological space and τ′ is a finer topology on X than τ.

Proof

Given: A Hausdorff topological space (X,τ), and a topology τ′ on X that is finer than τ

To prove: (X,τ′) is Hausdorff

Proof: We need to show that for points x≠y in X, there exist open sets U,V in the topology τ′ such that x∈U,y∈V, and U∩V is empty.

Since τ gives a Hausdorff topology, we can find open sets U,V in the topology τ, such that x∈U,y∈V and U∩V is empty. And since τ′ is finer than τ, the sets U,V satisfy the condition in τ′ as well.