Mapping cylinder: Difference between revisions

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Let <math>f:X \to Y</math> be a function. Then the '''mapping cylinder''' of <math>f</math> is defined as the quotient of the disjoint union of <math>X \times I</math> with <math>Y</math>, modulo the equivalence relation:
Let <math>f:X \to Y</math> be a function. Then the '''mapping cylinder''' of <math>f</math> is defined as the quotient of the disjoint union of <math>X \times I</math> with <math>Y</math>, modulo the equivalence relation:


<math>(x,1) \simeq f(x)</math>
<math>\! (x,1) \sim f(x)</math>
 
Here, <math>I = [0,1]</math> is the [[unit interval]].


==Facts==
==Facts==

Revision as of 23:10, 9 October 2010

Definition

Let f:XY be a function. Then the mapping cylinder of f is defined as the quotient of the disjoint union of X×I with Y, modulo the equivalence relation:

(x,1)f(x)

Here, I=[0,1] is the unit interval.

Facts

The significance of the mapping cylinder is that it is homotopy-equivalent to Y, and moreover the inclusion of X (say via x(x,0)) in the mapping cylinder is equivalent to the map f.

Thus, starting from an arbitrary continuous map, we have got a homotopy-equivalent map which is an inclusion.

Further, the inclusion of X in the mapping cylinder is a cofibration, which makes it even nicer.

Relation with other constructions

More general constructions

Name of construction Description of construction How the mapping cylinder is a special case
double mapping cylinder spaces X,Y,Z, with continuous maps from X to Y and X to Z, we take (X×I)YZ and collapse X×{0} and X×{1} onto Z and Y via the continuous maps Case where X=Z and the map XZ is the identity map.

More specific constructions

Name of construction How it arises as a special case
cone space Set Y as a one-point space and f:XY as the map sending everything to one point.