Complete regularity is hereditary: Difference between revisions
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The [[property of topological spaces]] of being [[completely regular space|completely regular]] is a [[hereditary property of topological spaces]]. | The [[property of topological spaces]] of being [[completely regular space|completely regular]] is a [[hereditary property of topological spaces]]. | ||
===Verbal statement=== | |||
Any subset of a [[completely regular space]] is completely regular in the [[subspace topology]]. | |||
==Definitions used== | |||
===Completely regular space=== | |||
{{further|[[completely regular space]]}} | |||
===Subspace topology=== | |||
{{further|[[subspace topology]]}} | |||
==Proof== | |||
===Proof outline=== | |||
* Pick a point and a closed subset of the subspace | |||
* Find a closed subset of the whole space, whose intersection with the subspace is the given subset | |||
* Find a continuous function separating the point, and the bigger closed subset, in the whole space | |||
* Restrict this continuous function to the subspace, and observe that this works | |||
Revision as of 00:05, 27 December 2007
This article gives the statement, and possibly proof, of a topological space property satisfying a topological space metaproperty
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This article gives the statement, and possibly proof, of a basic fact in topology.
Statement
Property-theoretic statement
The property of topological spaces of being completely regular is a hereditary property of topological spaces.
Verbal statement
Any subset of a completely regular space is completely regular in the subspace topology.
Definitions used
Completely regular space
Further information: completely regular space
Subspace topology
Further information: subspace topology
Proof
Proof outline
- Pick a point and a closed subset of the subspace
- Find a closed subset of the whole space, whose intersection with the subspace is the given subset
- Find a continuous function separating the point, and the bigger closed subset, in the whole space
- Restrict this continuous function to the subspace, and observe that this works