Contractibility is product-closed: Difference between revisions

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==Statement==
==Statement==


Let <math>X_i</math>, <math>i \in I</math>, be an indexed family of topological spaces. Then the product space, endowed with the [[product topology]], is contractible.
We describe the proof for two spaces; the same idea works in general:
Let <math>X</math> and <math>Y</math> be [[contractible space]]s. Then the product space <math>X \times Y</math> is contractible.
Let <math>X</math> and <math>Y</math> be [[contractible space]]s. Then the product space <math>X \times Y</math> is contractible.



Revision as of 21:04, 15 December 2007

Statement

Let Xi, iI, be an indexed family of topological spaces. Then the product space, endowed with the product topology, is contractible.

We describe the proof for two spaces; the same idea works in general: Let X and Y be contractible spaces. Then the product space X×Y is contractible.

Proof

Key idea

Suppose F:X×IX and G:Y×IY are contracting homotopies for X and Y. Then the map F×G defined as:

(F×G)(x,y,t)=(F(x,t),G(y,t))

is a contracting homotopy for X×Y.

Thus X×Y is contractible.