Normality is not product-closed: Difference between revisions
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==Example== | ==Example== | ||
An example is the [[Sorgenfrey plane]], which is a product of two copies of the [[Sorgenfrey line]]. | An example is the [[Sorgenfrey plane]], which is a product of two copies of the [[Sorgenfrey line]]. {{proofat|[[Sorgenfrey line is normal]], [[Sorgenfrey plane is not normal]]}} | ||
==Consequences== | ==Consequences== |
Revision as of 22:42, 15 December 2007
Statement
A product of normal spaces need not be normal.
Example
An example is the Sorgenfrey plane, which is a product of two copies of the Sorgenfrey line. For full proof, refer: Sorgenfrey line is normal, Sorgenfrey plane is not normal
Consequences
Since the property of being a completely regular space is closed under products, this gives a proof that the property of normality is strictly stronger than the property of complete regularity. Specifically, any example of a product of normal spaces which is not normal, is also an example of a completely regular space which is not normal.
Related facts
Binormality
Closely related to the fact that normality is not product-closed is the notion of a binormal space. A binormal space is a normal space whose product with the unit interval is also normal.
Stronger properties which are closed under products
Although normality is not closed under taking products, there are a number of properties slightly stronger than normality, which are closed under taking products. For instance:
Although a product of paracompact Hausdorff spaces need not be paracompact Hausdorff, it is true that a product of a paracompact Hausdorff space with a compact Hausdorff space is paracompact Hausdorff, and hence normal. Thus, paracompact Hausdorff spaces are binormal.