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In other words, any open subset containing a slice, contains an [[open cylinder]] that contains the slice.
In other words, any open subset containing a slice, contains an [[open cylinder]] that contains the slice.
==References==
===Textbook references===
* {{booklink-proved|Munkres}}, Page 168, Lemma 26.8, Chapter 3, Section 26 (the proof is given before the theorem, as Step 1 of the proof of Theorem 26.7 on page 167)

Revision as of 21:50, 20 July 2008

This fact is related to: compactness

This article is about the statement of a simple but indispensable lemma in topology

Statement

Let X be a compact space and A any topological space. Consider X×A endowed with the product topology. Suppose aA and U is an open subset of X×A containing the entire slice X×{a}. Then, we can find an open subset V of A such that:

aV, and X×VA

In other words, any open subset containing a slice, contains an open cylinder that contains the slice.

References

Textbook references

  • Topology (2nd edition) by James R. Munkres, More info, Page 168, Lemma 26.8, Chapter 3, Section 26 (the proof is given before the theorem, as Step 1 of the proof of Theorem 26.7 on page 167)