Compact times paracompact implies paracompact: Difference between revisions

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{{product computation}}
{{product computation|
 
left = compact space|
{{factrelatedto|compactness}}
right = paracompact space|
final = paracompact space}}


==Statement==
==Statement==

Revision as of 02:39, 17 July 2009

This article states and proves a result of the following form: the product of two topological spaces, the first satisfying the property Compact space (?) and the second satisfying the property Paracompact space (?), is a topological space satisfying the property Paracompact space (?).
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Statement

Verbal statement

The product of a compact space with a paracompact space (given the product topology), is paracompact

Symbolic statement

Let X be a compact space and Y a paracompact space. Then X×Y is paracompact.

Related results

Other results using the same proof technique:

Results used in proof

The key result used is the tube lemma, which exploits the compactness of X.

Proof

Let X be compact and Y paracompact. We need to prove that X×Y is paracompact.

Start off with an open cover of X×Y. For each yY, this yields an open cover of X×{y} (treated as a copy of X). By compactness, we can choose a finite subcover of the cover at each point, and this finite ... Fill this in later