Poincare polynomial: Difference between revisions

From Topospaces
m (5 revisions)
Line 26: Line 26:
===Product===
===Product===


When either of the spaces has torsion-free homology, the Poincare polynomial of the product of the spaces is the product of the Poincare polynomials. This is a corollary of the [[Kunneth formula]] (note that we are assuming that both spaces have finitely generated homology).
The Poincare polynomial of the product of the spaces is the product of the Poincare polynomials. This is a corollary of the [[Kunneth formula]] (note that we are assuming that both spaces have finitely generated homology).


A particular case of this (which can be proved directly using the [[exact sequence for join and product]] and does not require appeal to the Kunneth formula) is:
A particular case of this (which can be proved directly using the [[exact sequence for join and product]] and does not require appeal to the Kunneth formula) is:


<math>P(X \times S^m) = PX \times P(S^m)</math>
<math>P(X \times S^m) = PX \times P(S^m)</math>

Revision as of 23:52, 1 April 2011

This article describes an invariant of topological spaces that depends only on its homology groups

Definition

Given a topological space which has finitely generated homology, the Poincare polynomial of is defined as the generating function of its Betti numbers, viz the polynomial where the coefficient of is .

Note that for a space with homology of finite type, all the Betti numbers are well-defined, but infinitely many of them are nonzero, so we get a Poincare series instead of a Poincare polynomial.

The Poincare polynomial of is denoted .


Facts

Disjoint union

The Poincare polynomial of a disjoint is the sum of the Poincare polynomials of the individual spaces:

Wedge sum

The Poincare polynomial of a wedge sum of two path-connected spaces, is the sum of their polynomials minus 1.

Product

The Poincare polynomial of the product of the spaces is the product of the Poincare polynomials. This is a corollary of the Kunneth formula (note that we are assuming that both spaces have finitely generated homology).

A particular case of this (which can be proved directly using the exact sequence for join and product and does not require appeal to the Kunneth formula) is: