Compact times paracompact implies paracompact: Difference between revisions

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{{product computation}}
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{{result related to|compactness}}
{{factrelatedto|compactness}}
 
{{applicationof|tube lemma}}


==Statement==
==Statement==

Revision as of 00:09, 27 December 2007

This article states and proves a result of the following form: the product of two topological spaces, the first satisfying the property "{{{left}}}" is not a number. and the second satisfying the property "{{{right}}}" is not a number., is a topological space satisfying the property "{{{final}}}" is not a number..
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This fact is related to: compactness

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Statement

Verbal statement

The direct product of a compact space with a paracompact space, is paracompact.

Symbolic statement

Let be a compact space and a paracompact space. Then is paracompact.

Related results

Other results using the same proof technique:

Results used in proof

The key result used is the tube lemma, which exploits the compactness of .

Proof

Let be compact and paracompact. We need to prove that is paracompact.

Start off with an open cover of . For each , this yields an open cover of (treated as a copy of ). By compactness, we can choose a finite subcover of the cover at each point, and this finite ... Fill this in later