Totally disconnected implies T1: Difference between revisions

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Any [[totally disconnected space]] is a [[T1 space]].
Any [[totally disconnected space]] is a [[T1 space]].
==Facts used==
# [[uses::Closure of one-point subset implies irreducible]]
# [[uses::Irreducible implies connected]]


==Proof==
==Proof==

Revision as of 20:19, 13 January 2012

This article gives the statement and possibly, proof, of an implication relation between two topological space properties. That is, it states that every topological space satisfying the first topological space property (i.e., totally disconnected space) must also satisfy the second topological space property (i.e., T1 space)
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Statement

Any totally disconnected space is a T1 space.

Facts used

  1. Closure of one-point subset implies irreducible
  2. Irreducible implies connected

Proof

Given: A totally disconnected space , a point .

To prove: .

Proof: We prove this by noting that the closure is connected, on account of being an irreducible space. Thus, by the definition of totally disconnected, it must be a singleton subset.