Contractibility is product-closed: Difference between revisions

From Topospaces
No edit summary
m (4 revisions)
(No difference)

Revision as of 19:42, 11 May 2008

This article gives the statement, and possibly proof, of a topological space property satisfying a topological space metaproperty
View all topological space metaproperty satisfactions | View all topological space metaproperty dissatisfactions
|

Property "Page" (as page type) with input value "{{{property}}}" contains invalid characters or is incomplete and therefore can cause unexpected results during a query or annotation process.Property "Page" (as page type) with input value "{{{metaproperty}}}" contains invalid characters or is incomplete and therefore can cause unexpected results during a query or annotation process.

Statement

Symbolic statement

Let Xi, iI, be an indexed family of topological spaces. Then the product space, endowed with the product topology, is contractible.

We describe the proof for two spaces; the same idea works in general: Let X and Y be contractible spaces. Then the product space X×Y is contractible.

Proof

Key idea

Suppose F:X×IX and G:Y×IY are contracting homotopies for X and Y. Then the map F×G defined as:

(F×G)(x,y,t)=(F(x,t),G(y,t))

is a contracting homotopy for X×Y.

Thus X×Y is contractible.