Hausdorffness is product-closed: Difference between revisions
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===Proof outline=== | ===Proof outline=== | ||
The proof has the following | The proof has the following three steps: | ||
* Write down both points in the product space as tuples | * Write down both points in the product space as tuples | ||
* Find a coordinate where they differ, and separate the projections on that coordinate, by disjoint open sets in that coordinate (this is where we use that each space is Hausdorff) | * Find a coordinate where they differ, and separate the projections on that coordinate, by disjoint open sets in that coordinate (this is where we use that each space is Hausdorff) | ||
* Use the open cylinders corresponding to these disjoint open subsets, to separate the original two points | * Use the open cylinders corresponding to these disjoint open subsets, to separate the original two points | ||
Revision as of 23:53, 26 December 2007
This article gives the statement, and possibly proof, of a topological space property satisfying a topological space metaproperty
View all topological space metaproperty satisfactions | View all topological space metaproperty dissatisfactions
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Property "Page" (as page type) with input value "{{{property}}}" contains invalid characters or is incomplete and therefore can cause unexpected results during a query or annotation process.Property "Page" (as page type) with input value "{{{metaproperty}}}" contains invalid characters or is incomplete and therefore can cause unexpected results during a query or annotation process.
Statement
Property-theoretic statement
The property of topological spaces of being a Hausdorff space is a product-closed property of topological spaces.
Verbal statement
An arbitrary (finite or infinite) product of Hausdorff spaces, when endowed with the product topology, is also a Hausdorff space.
Definitions used
Hausdorff space
Further information: Hausdorff space
A topological space is Hausdorff if given distinct points , there exist disjoint open sets containing and .
Product topology
Further information: Product topology
Suppose is an indexing set, and a family of topological spaces, . Then if is the Cartesian product of the s, the product topology on is a topology with subbasis given by all the open cylinders: all sets of the form such that for all but one , , and for the one exceptional , is an open subset of .
Proof
Proof outline
The proof has the following three steps:
- Write down both points in the product space as tuples
- Find a coordinate where they differ, and separate the projections on that coordinate, by disjoint open sets in that coordinate (this is where we use that each space is Hausdorff)
- Use the open cylinders corresponding to these disjoint open subsets, to separate the original two points