Compactness is weakly hereditary

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This article gives the statement, and possibly proof, of a topological space property (i.e., compact space) satisfying a topological space metaproperty (i.e., weakly hereditary property of topological spaces)
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Statement

Property-theoretic statement

The property of topological spaces of being compact satisfies the metaproperty of being weakly hereditary: in other words, it is inherited by closed subsets.

Verbal statement

Any closed subset of a compact space is compact (when given the subspace topology).

Related facts

Weakly hereditary for properties related to compactness


Proof

Proof in terms of open covers

Given: a compact space, a closed subset (given the subspace topology)

To prove: Consider an open cover of by open sets with , an indexing set. The have a finite subcover.

Proof:

  1. By the definition of subspace topology, we can find open sets of such that , thus the union of the s contains .
  2. Since is closed, we can throw in the open set , and get an open cover of the whole space .
  3. Since the whole space is compact, this open cover has a finite subcover. In other words, there is a finite subcollection of the s, that, possibly along with , covers the whole of .
  4. By throwing out , we get a finite collection of s whose union contains . The corresponding now form a finite subcover of the original cover of .

Proof in terms of finite intersection property

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References

Textbook references

  • Topology (2nd edition) by James R. Munkres, More info, Page 165, Theorem 26.2, Chapter 3, Section 26
  • Lecture Notes on Elementary Topology and Geometry (Undergraduate Texts in Mathematics) by I. M. Singer and J. A. Thorpe, More info, Page 12 (Theorem 4)