Metric is jointly continuous

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Revision as of 02:23, 24 January 2008 by Vipul (talk | contribs) (New page: ==Statement== Let <math>(X,d)</math> be a metric space. Then <math>X</math> is also a topological space in the induced topology, and we can consider the metric as a map of topological...)
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Statement

Let be a metric space. Then is also a topological space in the induced topology, and we can consider the metric as a map of topological spaces . This map is jointly continuous, i.e. it is continuous from given the product topology.

Proof

It suffices to show that inverse images of open subsets of the form and are open subsets of . We will use the triangle inequality to prove this.