Hausdorffness is hereditary

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This article gives the statement, and possibly proof, of a topological space property (i.e., Hausdorff space) satisfying a topological space metaproperty (i.e., subspace-hereditary property of topological spaces)
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Statement

Any subspace of a Hausdorff space is Hausdorff in the subspace topology.

Definitions used

Hausdorff space

Further information: Hausdorff space

A topological space X is Hausdorff if given distinct points a,bX there exist disjoint open subsets U,V containing a,b respectively.

Subspace topology

Further information: subspace topology

If A is a subset of X, we declare a subset V of A to be open in A if V=UA for an open subset U of X.

Proof

Given: A topological space X, a subset A of X. Two distinct points x1,x2A.

To prove: There exist disjoint open subsets U1,U2 of A such that x1U1,x2U2.

Proof:

Step no. Assertion/construction Facts used Given data used Previous steps used Explanation
1 x1,x2 are distinct points of X x1,x2 are distinct points of A
AX
2 There exist disjoint open subsets V1,V2 of X such that x1V1,x2V2. X is Hausdorff Step (1) Step-given direct
3 Define U1=V1A and U2=V2A.
4 U1,U2 are open subsets of A. definition of subspace topology Steps (2), (3) By Step (2), V1,V2 are open, so by the definition of subspace topology, U1,U2 are open as per their definitions in Step (3).
5 U1,U2 are disjoint. Steps (2), (3) follows directly from V1,V2 being disjoint
6 x1U1,x2U2 x1,x2A Steps (2), (3) By Step (3), U1=V1A. By Step (2), x1V1, and we are also given that x1A, so x1V1A=U1. Similarly, x2U2.
7 U1,U2 are the desired open subsets of A. Steps (4)-(6) Step-combination direct, it's what we want to prove.

This proof uses a tabular format for presentation. Learn more about tabular proof formats|View all pages on facts with proofs in tabular format

References

Textbook references

  • Topology (2nd edition) by James R. Munkres, More info, Page 100, Theorem 17.11, Page 101, Exercise 12 and Page 196 (Theorem 31.2 (a))